Answer with Step-by-step explanation:
Since we have given that
Initial velocity = 50 ft/sec =
![v_0](https://img.qammunity.org/2020/formulas/physics/high-school/lf5qdpqen4citmsxuem9hhcjcl08zkznft.png)
Initial height of ball = 5 feet =
![h_0](https://img.qammunity.org/2020/formulas/physics/college/kyxt34qr802z65dwx526rs04ygsm4gpfg7.png)
a. What type of function models the height (ℎ, in feet) of the ball after tt seconds?
As we know the function for height h with respect to time 't'.
![h(t)=-16t^2+v_0t+h_0\\\\h(t)=-16t^2+50t+5](https://img.qammunity.org/2020/formulas/mathematics/high-school/zti5gequm3bqllmxzvrcnqpkpp61yq8uu3.png)
b. Explain what is happening to the height of the ball as it travels over a period of time (in tt seconds).
What function models the height, ℎ (in feet), of the ball over a period of time (in tt seconds)?
if it travels over a period of time then time becomes continuous interval . so it will use integration over a period of time
Our function becomes,
![h(t)=\int\limits^t_0 {-16t^2+50t+5} \, dt](https://img.qammunity.org/2020/formulas/mathematics/high-school/dbxxqu6lkyapo0uqk7rpdct2cg1n4os133.png)