Question

Check all of the following that are solutions to the system shown below.

y = -x 2 - x + 2 and x + y = -2

Answer 1

(2,-4),(-2,0)

Explanation:

Given system of equations :

`y=-x^(2)-x+2;x+y=-2`

On substituting
`y=-2-x` from second equation in the first equation,

`-2-x=-x^(2)-x+2\\x^(2)=4\\x=\pm2`

From first equation, when
`x=2`,
`y=-4`;

when
`x=-2`,
`y=0`

∴
`x=2,y=-4` and
`x=-2,y=0` are the solutions to the system given.