Answer:
(g ο f)(0) < (f ο g)(3.5) < (g ο f)(- 2) < (f ο g)(0) < (g ο f)(3.5) < (f ο g)(-2)
Explanation:
We are given that f(x) = 2x² and g(x) = x - 2
Therefore, (f ο g)(x) = f[]g(x)] = 2(x - 2)² ......... (1)
and (g ο f)(x) = g[f(x)] = 2x² - 2 ........... (2)
Therefore, (f ο g)(-2) = 32 {from equation (1)}
(f ο g)(3.5) = 4.5 {From equation (1)}
And (f ο g)(0) = 8 {From equation (1)}
Now, (g ο f)(- 2) = 6 {From equation (2)}
(g ο f)(3.5) = 22.5 {From equation (2)}
And (g ο f)(0) = -2 {From equation (2)}
Therefore, if we arrange those values from least to greatest value, then we will get
(g ο f)(0) < (f ο g)(3.5) < (g ο f)(- 2) < (f ο g)(0) < (g ο f)(3.5) < (f ο g)(-2) (Answer)