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Consider the standard form equation 2x-Ry=30. What value of R causes the graph to have a y-intercept of 5?

Consider the standard form equation 2x-Ry=30. What value of R causes the graph to-example-1
Consider the standard form equation 2x-Ry=30. What value of R causes the graph to-example-1
Consider the standard form equation 2x-Ry=30. What value of R causes the graph to-example-2
User Ian Wong
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8.4k points

1 Answer

5 votes

Answer:

R = 6

Explanation:

Given the equation of the line is 2x - Ry = 30

We know that the equation of a line with a as x-intercept and b as y-intercept is
(x)/(a) +(y)/(b) =1

Now convert the above given line to the standard form

Divide the line by 30 we get


(2x)/(30)-(Ry)/(30) =(30)/(30)


(x)/(15) -(y)/((30)/(R) ) =1

Here the y-intercept is 30/R

Given y-intercept = 5


(30)/(R) =5

R = 6

User Ben Carp
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8.0k points