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3 votes
Given g(x)= root x-4 and h(x) = 2x-8 what is g(h(10))

User Billybonks
by
5.6k points

2 Answers

3 votes

Answer:2^*2

Explanation:

User JeffbRTC
by
5.8k points
3 votes

The value of g(h(10)) is
2 √(2)

Explanation:

Given that,


g(x)=√((x-4)) and h(x) = 2x-8

To find g(h(10)) first find h(10) that implies

h(x) = 2x-8


h(10)=(2 * 10)-8

h(10) = 20 - 8

h(10) = 12

Now, g(h(10)) = g(12)


g(x)=√((x-4))


g(12)=√((12-4))


g(12)=√(8)


√(8) Can be written as
=\sqrt{2 * 2^(2)}


g(12)=√(2) * \sqrt{2^(2)}


g(12)=2 √(2)


\therefore
g(h(10))=2 √(2)

Therefore
g(h(10))=2 √(2)
for the Given g(x) = root x-4 and h(x) = 2x-8.

User Jagjeet Singh
by
5.8k points
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