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(p-2)^2=-9 Solve for p​

User Ehvince
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1 Answer

5 votes

Answer:


\displaystyle \boxed{±3i + 4 = p}

Explanation:

(p - 2)² = −9

p² - 4p + 4 = −9

+ 9 + 9

____________

p² - 4p + 13

Since this equation is unfactorable with rational numbers, apply the Quadratic Formula:


\displaystyle -b ± (√(b^2 - 4ac))/(2a) = p


\displaystyle 4 ± (√(4^2 - 4[1][13]))/(2[1]) = p


\displaystyle 4 ± (√(16 - 52))/(2) = p


\displaystyle 4 ± (√(-36))/(2) = p


\displaystyle 4 ± (6i)/(2) = p


\displaystyle 4 ± 3i = p

** The above answer is written in reverse, which is the exact same result.

I am joyous to assist you anytime.

User Nuclearnova
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