Question

Simplified radical form of 4800 feet how many seconds was the diver in a free fall? Using functions (t)=16t^2 models the distance s (t), in feet , that an object falls in t seconds.

Answer 1

The diver will be in free fall for
`10√(3)` seconds.

Explanation:

The distance in feet, that an object falls in t seconds is given by the function
`h(t) = 16t^(2)`.

Now, given that the height is 4800 feet and we have to calculate the number of seconds the diver was in a free fall.

Therefore,
`4800 = 16t^(2)`

⇒
`t^(2) = (4800)/(16) = 300`

⇒
`t = √(300) = √(100 * 3) = 10√(3)` seconds.

Therefore, the diver will be in free fall for
`10√(3)` seconds. (Answer)