Question

an electrician has 4.1 meters of wire. How much stripes 7/10m long can he cut? How much wire will he have left over?

Answer 1

From 4.1 meters wire, we can make 5 stripes with 0.6 meters wire being left.

Solution:

Given that, an electrician has 4.1 meters of wire.

We have to find

1) Number of stripes 7/10m long can he cut:

Now, we know that, number of stripes he can make
`=\frac{\text {available length of wire}}{\text {Length of each stripe}}=(4.1)/((7)/(10))`

`\Rightarrow (4.1)/((7)/(10))=4.1 * (10)/(7)=(41)/(7)=5.857`

So, he can make 5 full stripes. We have to neglect fractional value as that is not considered as stripe.

2) Measure of left over wire:

No, we know that, remaining length of wire = total wire length-used length wire

`\begin{array}{l}{\text { Length of left over wire }=4.1 \text { meters- number stripes used }* \text {length of each stripe }} \\\\ {\text { Length of left over wire }=4.1-5 * (7)/(10)=4.1-(7)/(2)=4.1-3.5=0.6 \text { meters }}\end{array}`

So, 0.6 meters of wire is left.

Answer 2

`5` such strips of
`(7)/(10)\ m` can be cut and
`(6)/(10)\ m` would be left over.

Explanation:

Given is
`4.1= (41)/(10)\ m` length of a wire.

We have to cut strips of
`(7)/(10)\ m`

If we factorize
`41 \ by \ 7`

We get
`5` full and
and
`(6)/(7)`

Similarly , if we factorize
`(41)/(10) \ by \ (7)/(10)`

We get full
`5 \ strips` and another
`(6)/(10) \ m` would be left.