Question

A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an acceleration of 4.5 m/s squared

Answer 1

The force required to move the quarterback with linebacker is 1215 N

Step-by-step explanation:

`\text { Mass of linebacker } \mathrm{m}_(2)=150 \mathrm{kg}`

`\text { Mass of quarterback } \mathrm{m}_(2)=120 \mathrm{kg}`

`\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^(2)`

Using Newton's second law, it is established that F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object
`\left(m_(1)+m_(2)\right)`

Now consider both
`\mathrm{m}_(1) \text { and } \mathrm{m}_(2)`as a system, so net force acting on the system is
`\text { Force }=\left(m_(1)+m_(2)\right) a`

Substitute the given values in the above formula,

`\text { Force }=(150+120) \mathrm{kg} * 4.5 \mathrm{m} / \mathrm{s}^(2)`

`\text { Force }=270 \mathrm{kg} * 4.5 \mathrm{m} / \mathrm{s}^(2)`

Force = 1215 N

1215 N is the force required to move the quarterback with linebacker.