Answer: The cost to tile the floor is $318.24.
Explanation:
Since we have given that
Dimensions of floor is 12 by 17 foot.
So, Area of floor would be
![12* 17\\\\=204\ sq.\ foot](https://img.qammunity.org/2020/formulas/mathematics/college/lw9xmtuqe4nc4t6ddthoqby7w55hebj1ne.png)
As we know that 1 foot = 12 inch
So, Area of floor would be
![204* (12)^2\\\\=204* 144\\\\=29376\ sq.\ foot](https://img.qammunity.org/2020/formulas/mathematics/college/qs4b0iwm3do46n93e4lrbx28jmw8nn036g.png)
Dimension of brick tiles is given by
![3(5)/(8)\ by\ 7(5)/(8)\ by\ (1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/college/2lbrypmd2kmo98lw0ckrzvzluhwtummwrr.png)
So, Area of brick tiles is given by
![2(lb+bh+lh)\\\\=2((29)/(8)* (61)/(8)+(61)/(8)* (1)/(2)+(29)/(8)* (1)/(2))\\\\=2((1769)/(64)+(61)/(16)+(29)/(16))\\\\=2* (1769+244+116)/(64)\\\\=(2129)/(32)](https://img.qammunity.org/2020/formulas/mathematics/college/s672b82g2r1crd2qrx0vp0zst3szs28qk1.png)
So, Number of clay brick would be
![29376/ (2129)/(32)\\\\=29376* (32)/(2129)\\\\=(29376* 32)/(2129)\\\\=441.53\\\\\approx 442](https://img.qammunity.org/2020/formulas/mathematics/college/ly38taib9jyl5k6e2kqzb3k0i2ns77odvc.png)
cost of each clay brick = $0.72
So, Total cost of flooring would be
![442* 0.72\\\\=\$318.24](https://img.qammunity.org/2020/formulas/mathematics/college/n9szt2l3mpd82rvw3j5m1derkx7pa14mqi.png)
Hence, The cost to tile the floor is $318.24.