Answer:
Since p >0.05 at 5% significance level we reject that it is cheaper to eat at a restaurant than to cook the meal yourself!
Explanation:
Given that the mean cost of a steak, broccoli, and ride at the grocery store is $13.04.
Sample size n = 100
Sample mean =
![\bar x = 12.75\\s=2](https://img.qammunity.org/2020/formulas/mathematics/college/u57csgdx6pc6qp4t28arlo6wdgzemu186o.png)
Std error of sample =
![(2)/(√(100) ) =0.20](https://img.qammunity.org/2020/formulas/mathematics/college/hil9xy0j62crt16em9ypfpbet629vbhucm.png)
![H_0: \bar x = 13.04\\H_a: \bar X <13.04](https://img.qammunity.org/2020/formulas/mathematics/college/dvd4oh9px0cr9xvx4nxt06fudwn1f1hc8z.png)
(Left tailed test)
Mean difference =
![13.04-12.75=0.29](https://img.qammunity.org/2020/formulas/mathematics/college/jtzsyd88e47vgfsslmxioat8yxsjkn3x5v.png)
Test statistic = t = mean diff/std error
=
![(0.29)/(0.20) =1.45](https://img.qammunity.org/2020/formulas/mathematics/college/haa4et4o5dwqq4cmnr4a2ss0ltf2xtk15a.png)
p value one tailed =0.075
Since p >0.05 at 5% significance level we reject that it is cheaper to eat at a restaurant than to cook the meal yourself!