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The director of admissions at the University of Maryland, University College is concerned about the high cost of textbooks for the students each semester.

A sample of 25 students enrolled in the university indicates that X (bar) = $315.4 and s = $43.20.a. Using the 0.10 level of significance, is there evidence that the population mean is above $300?
b. What is your answer in (a) if s = $75 and the 0.05 level of significance is used?
c. What is your answer in (a) if X (bar) = $305.11 and s = $43.20?
d. Based on the information in part (a), what decision should the director make about the books used for the courses if the goal is to keep the cost below $300?

User Cledoux
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Answer:

a. There is evidence that the population mean is above $300.

b. There is no evidence that the population mean is above $300.

c. There is no evidence that the population mean is above $300.

d. The director could ask for cheaper similar books.

Explanation:

Let X be the random variable that represents the cost of textbooks. We have observed n = 25 values,
\bar{x} = 315.4 and s = 43.20. We suppose that X is normally distributed.

We have the following null and alternative hypothesis


H_(0): \mu = 300 vs
H_(1): \mu > 300 (upper-tail alternative)

We will use the test statistic


T = \frac{\bar{X}-300}{S/√(25)} and the observed value is


t_(0) = (315.4 - 300)/(43.20/√(25)) = 1.7824.

If
H_(0) is true, then T has a t distribution with n-1 = 24 degrees of freedom.

a. The rejection region is given by RR = {t | t >
t_(0.9)} where
t_(0.9) = 1.3178 is the 90th quantile of the t distribution with 24 df, so, RR = t . Because the observed value satisty 1.7824 > 1.3178, there is evidence that the population mean is above $300.

b. If s = 75, then the observed value is
t_(0) = (315.4 - 300)/(75/√(25)) = 1.0267. The rejection region for a 0.05 level of significance is RR = {t | t >
t_(0.95)} where
t_(0.95) = 1.7108 is the 95th quantile of the t distribution with 24 df, so, RR = t . Because the observed value does not fall inside the rejection region, there is no evidence that the population mean is above $300.

c. If
\bar{x} = 305.11 and s = 43.20, the observed value is
t_(0) = (305.11 - 300)/(43.20/√(25)) =  0.5914. For RR = t we have that the observed value does not fall inside RR, therefore, there is no evidence that the population mean is above $300.

d. Because the director of admissions is concerned about the high cost of textbooks, and there is evidence that the population mean of costs is above $300, the director could ask for cheaper similar books.

User Vikas Gupta
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