Question

Show that X^2-8x+20 can be written in the form (x-a)^2+a

Answer 1

Answer:x^2 + 8x + 20

a = 1

b = 8

c = 20

Discriminant = b^2 - 4ac

=> 8^2 - 4(1)(20)

=> 64 - 80

=> -16

As -16<0

So, equation has no real roots

I hope this will help you

(-:

Explanation:

Answer 2

The equation
`x^2-8x+20` can be written in the form
`(x-a)^2+a` as
`(x-4)^(2) +36`

How can we express the equation?

Given that;

The quadratic function =
`x^2-8x+20`

We can make use of the Complete the square method so as to arrive at the expression
`(x-a)^2+a`

`x^(2) +8x-((8)/(2) )^(2) +((8)/(2) )^(2) +20`

`x^2-8x-4^(2) +4^(2) +20`

`(x-4)^(2) +16+20`

`(x-4)^(2) +36`

Therefore equation
`x^2-8x+20` can be written in the form
`(x-a)^2+a` as
`(x-4)^(2) +36`