Answer:
[H₂] = 13 M
[N₂] = 12 M
Step-by-step explanation:
Let´s consider the following reaction at equilibrium.
3 H₂(g) + N₂(g) ⇄ 2 NH₃(g)
To find out the initial concentrations we will use an ICE chart. We recognize 3 stages: Initial, Change and Equilibrium and complete each row with the concentration or change in concentration. We will use letters for the unknown data.
3 H₂(g) + N₂(g) ⇄ 2 NH₃(g)
I a b 0
C -3x -x +2x
E a - 3x b - x 2x
We know that,
[NH₃] = 2x = 5.1 M ⇒ x = 2.6 M
Then,
[H₂] = 5.6 M = a - 3x ⇒ a = 13 M
[N₂] = 9.3 M = b - x ⇒ b = 12 M