Answer:
2 meter square per minute
Explanation:
Given the circumference is of the circle is increasing at a rate of 0.5 m/minute
We know that C = 2πr
We know that the area of the circle(A) = π
![r^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i4cctlhbdmsh9gm8w3i110encr9k0joluz.png)
Let π=a
![r=(C)/(2a)](https://img.qammunity.org/2020/formulas/mathematics/high-school/85xy7bzuyg6spufqpklhk48rrzo07xu99o.png)
A = a
![((C)/(2a))^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/8q4l32fphmcwjnet3e4eg475s6cn11uw6d.png)
![A=(C^2)/(4a)](https://img.qammunity.org/2020/formulas/mathematics/high-school/caiq0hqxzrlmzxhwpfv4i0mpk7q5s9g0sy.png)
Differentiate both sides with respect to time
![(dA)/(dt)=(C)/(2a)(dC)/(dt)](https://img.qammunity.org/2020/formulas/mathematics/high-school/rj6l3wid3fe4qwrcboes7g1yqkr6o0uyp0.png)
C at r= 4 is C = 8a
Given
= 0.5
= 2