Question

A 4.0-kg falcon catches a 1.0-kg dove from behind in midair. What is their velocity after impact if the falcon’s velocity is initially 3.0 m/s and the dove’s velocity is 2.0 m/s in the same direction?

Answer 1

V = 2.8 m/s

Step-by-step explanation:

It is given that,

Mass of falcon,
`m_1=4\ kg`

Mass of dove,
`m_2=1\ kg`

Initial velocity of falcon,
`u_1=3\ m/s`

Initial velocity of dove,
`u_2=2\ m/s`

When the falcon catches the dove, the momentum remains conserved. Using the formula for the conservation of momentum as :

`m_1u_1+m_2u_2=(m_1+m_2)V`

V is the velocity after impact

`V=(m_1u_1+m_2u_2)/((m_1+m_2))`

`V=(4* 3+1* 2)/((4+1))`

V = 2.8 m/s

So, their velocity after the impact is 2.8 m/s. Hence, this is the required solution.