Question

A sample of oxygen gas in one container has a volume of 20.0mililiter at 297 K and 101.3 kPa. The entire sample is transferred to another container where the temperature is 283 K and the pressure is 94.6 kPa. Which is correct numerical setup for calculating the new volume of this sample of oxygen gas

Show work please

Answer 1

Answer:
`V_2=(101.3kPa* 20.0ml* 283K)/(297K* 94.6kPa)`

Step-by-step explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

`V_2=(P_1V_1T_2)/(T_1P_2)`

where,

`P_1` = initial pressure of gas = 101.3 kPa

`P_2` = final pressure of gas = 94.6 kPa

`V_1` = initial volume of gas = 20.0 ml

`V_2` = final volume of gas = ?

`T_1` = initial temperature of gas =
`297K`

`T_2` = final temperature of gas =
`283K`

Now put all the given values in the above equation, we get the final volume of gas.

`V_2=(101.3kPa* 20.0ml* 283K)/(297K* 94.6kPa)`

`V_2=20.4ml`

Thus the correct numerical setup for calculating the new volume is
`(101.3kPa* 20.0ml* 283K)/(297K* 94.6kPa)`