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The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of .2 inches.

What is the probability that a randomly selected sample of 4 sheets will have an average length of less than 29.9 inches long?

User FelixHJ
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1 Answer

2 votes

Answer: 0.0668

Explanation:

Given : The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

i.e.
\mu=30.5 and
\sigma=0.2

Let x denotes the lengths of aluminum-coated steel sheets.

Then the probability that a randomly selected sample of 4 sheets will have an average length of less than 29.9 inches long will be :-


P(x<29.9)=P((x-\mu)/((\sigma)/(√(n)))<(29.9-30.05)/((0.2)/(√(4))))\\\\=P(z<-1.5)=1-P(z<1.5)\ \ [\because\ P(Z<-z)=1-P(Z<z)]


=1-0.9332= 0.0668 [by using the z-value table ]

Hence, the required probability = 0.0668

User Systemhalted
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