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On a part time job you are asked to bring a cylindrical iron rod of density 7800 kg/m^3, length 81.2 cm and diameter 2.75 cm from a storage room to a machinist. Calculate the weight of the rod, w. The acceleration due to gravity, g= 9.81 m/s^2.w= 36.9 NNow that you know the weight of the rod, do you think that you will be able to carry the rod without a cart? Yes or No?

1 Answer

3 votes

Answer:

3.76188 kg

36.9040428 N

Yes

Step-by-step explanation:

g = Acceleration due to gravity = 9.81 m/s²

L = Length of rod = 81.2 cm

d = Diameter of rod = 2.75 cm

r = Radius =
(d)/(2)=(2.75)/(2)=1.375\ cm

A = Area of the cylinder =
\pi r^2

v = Volume =
L* A

m = Mass

Density


\rho=(m)/(v)\\\Rightarrow m=\rho* v\\\Rightarrow m=\rho* L* A\\\Rightarrow m=7800* 0.812* \pi* 0.01375^2\\\Rightarrow m=3.76188\ kg

The mass of the rod is 3.76188 kg.

As the the mass of the rod is 3.76188 kg I will be able to carry the rod.

Weight


W=mg\\\Rightarrow W=3.76188* 9.81\\\Rightarrow W=36.9040428\ N

The weight of the rod is 36.9040428 N

User Emil George James
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