Answer:
2nd 4th and 5th theoretical probabilities are equal to 1/3.
Explanation:
If a dice with six faces, having numbers (1-6) on each face is being rolled.
We will use the formula
![P=\frac{\text{favorable outcome}}{\text{total number of possible outcomes}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/6gh3qw76qtpg1ct9uzlw4b5d8iz58xwu6b.png)
(1) rolling an even number on the first roll.
Favorable outcome = 2,4,6 (3 numbers)
![P=(3)/(6)=(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6jxgxtu5c0ojpga4kepelds5d9e7b6db6q.png)
(2) Landing on a star space on the first roll.
Maximum numbers of stars to be reached in first roll = 2
![P=(2)/(6)=(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l4w1benrh759eji7llfo8uf00uyb5abvc6.png)
(3) Landing at Cat Town on the first roll is not possible because it is at 9th place. and we can reach at 6 place on first roll only.
Therefore,
=0
(4) Not landing on a question mark or star on the first roll.
Only 1 and 2 place has not question mark or star out of 6 places.
Favorable outcome will be = 2 (1 and 2)
![P=(2)/(6)=(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l4w1benrh759eji7llfo8uf00uyb5abvc6.png)
(5) Rolling a number greater than 4 on the first roll.
Favorable outcome = 2 ( 5 and 6)
![P=(2)/(6)=(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l4w1benrh759eji7llfo8uf00uyb5abvc6.png)
Therefore, 2nd 4th and 5th theoretical probabilities are equal to 1/3.