Question

I don’t what is the answer?

Answer 1

A) SSS

Explanation:

For the given figure:

Given:

`AB\cong DC`

`AC\cong DB`

To prove

`\triangle ABC\cong \triangle DCB`

In Δ ABC and ΔDCB

`AB\cong DC` [Given]

`AC\cong DB` [Given]

`BC\cong CB` [ By reflexive property of congruence side BC

congruent to itself ]

`\triangle ABC\cong \triangle DCB` [SSS congruence postulate]