Question

What I the equation in standard form of the line that passes through the points(4,-8) and has a slope of 1/4

Answer 1

Standard form of the line with point (4,-8) and slope of 1/4 is

-x + 4 y = -36.

Explanation:

The slope of the line equation = 1/4

The point is given as (4,-8).

Now, by POINT SLOPE formula,

The line equation with slope m nad point (x0,y0) is given as:

(y - y0) = m (x -x0)

So, the line equation here is given as

`y -(-8)  =  (1)/(4) (x -4)\\\implies 4(y + 8)  = x - 4\\4 y + 32 = x - 4\\4y = x - 36`

Now, the standard form of line equation is Ax + By = C

Here, 4y = x - 36 ⇒ 4y - x = -36

or, -x + 4y = -36 is the standard form.

Hence,standard form of the line with point (4,-8) and slope of 1/4

is -x + 4y = -36.