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What is the area of a sector of a circle with a radius of 6 inches and formed by a central angle that measures 90°?

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Explanation:

The area of a sector can be written as a fraction of the area of a circle:

A = (θ/360) πr²

Given θ = 90° and r = 6 in:

A = (90/360) π (6)²

A = (1/4) 36π

A = 9π

A ≈ 28.3

The area of the sector is 9π in² or approximately 28.3 in².

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