Question

A simple ac circuit consists of an inductor connected across the terminals of an ac power source. If the frequency of the ac source is decreased by a factor of four, what happens to the reactance of the inductor

Answer 1

reactance of the inductor increases by a factor of four.

Step-by-step explanation:

Reactance of inductor X_L = Lω

`X_L= L(2\pi f)`

X_L∝f

`(X_L_2)/(X_L_1) =(f_2)/(f_1)`

Given
`f_2 =(f_1)/(4)`

⇒f_2= f_1/4

`(X_L_2)/(X_L_1) = (1)/(4)`

therefore option we write it increases by a factor of four.