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When you take your 1900 kg car out for a spin, you go around a corner of radius 53 m with a speed of 13 m/s. If the co-efficient of friction between your tires and the road is 0.75, do you think you would be safe and make a round without skidding off?

User Kayoz
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Answer:

Yes, you would be safe without skidding off

Step-by-step explanation:

In this situation the sum of forces on the car would be:


F_f = m*(V^2)/(R)


F_f = 1900*(13^2)/(53)


F_f = 6058.5N

And the maximum friction force is:


F_fmax = \mu*N


F_fmax = \mu*m*g


F_fmax = 0.75*1900*10


F_fmax = 14250N

Since the required force is smaller than the maximum force, we can say it will not skid off

User Siraj Alam
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