Question

A manufacturing firm tests job applicants. Test scores are normally distributed with a mean of 500 and a standard deviation of 50. What is the probability that the candidate score is 600 or greater

Answer 1

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228

Explanation:

Step(i):-

Given mean of the Population = 500

Given standard deviation of the Population = 50

Let 'X' be the random variable in normal distribution

Given X = 600

`Z = (x-mean)/(S.D) = (600-500)/(50) = (100)/(50) =2`

Step(ii):-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = P(z≥2)

= 0.5 - A(2)

= 0.5 -0.4772

= 0.0228

Final answer:-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228