Question

The molar enthalpy of fusion (ΔH°) of bromine is 10.570 kJ/mol, and the molar entropy of fusion (ΔS°) of bromine is 39.750 J/mol K. Using this information, estimate the freezing point of bromine. (You must answer in Kelvin.)

Answer 1

265.91194 K

Step-by-step explanation:

`\Delta H^(\circ)` = Molar enthalpy of fusion = 10.57 kJ/mol

`\Delta S^(\circ)` = Molar entropy of fusion = 39.75 J/mol

`T_f` = Freezing point

Molar entropy of fusion is given by

`\Delta S^(\circ)=(\Delta H^(\circ))/(T_f)\\\Rightarrow T_f=(\Delta H^(\circ))/(\Delta S^(\circ))\\\Rightarrow T_f=(10.57* 10^3)/(39.75)\\\Rightarrow T_f=265.91194\ K`

The freezing point of bromine is 265.91194 K