Question

A 7382 N piano is to be pushed up a(n) 2.16 m frictionless plank that makes an angle of 22.7 ◦ with the horizontal. Calculate the work done in sliding the piano up the plank at a slow constant rate. Answer in units of J.

Answer 1

Work done, W = 6153.31 Joules

Step-by-step explanation:

It is given that,

Weight of piano, W = F = 7382 N

It is pushed 2.16 meters friction less plank

The angle with horizontal,
`\theta=22.7^(\circ)`

When the piano slide up plank at a slow constant rate. The y component of force is taken into consideration. The net force acting on it is given by :

`F_y=F\ sin\theta`

Work done is given by :

`W=F_y* d`

`W=F\ sin\theta * d`

`W=7382 sin(22.7) * 2.16`

W = 6153.31 Joules

So, the work done in sliding the piano up the plank is 6153.31 Joules. Hence, this is the required solution.