Question

A copper wire has a radius of 4.1 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends of the wire, the wire stretches by 5.0×10−3 of its original length. What is the tensile stress on the wire? Young's modulus for copper is 11×1010Pa.

Answer 1

tensile stress = 55 x 10⁷ Pa

Step-by-step explanation:

given,

radius of the copper wire = 4.1 mm = 0.0041 m

the wire stretches = 5.0×10⁻³ l

l = original length

young's modulus of copper = 11 x 10¹⁰ Pa

strain =
`(\Delta L)/(L) = 5 * 10^(-3)`

`young\ modulus = (stress)/(strain)`

`young\ modulus = (stress)/(strain)`

tensile stress = young's modulus x strain

tensile stress = 11 x 10¹⁰ x 5.0×10⁻³

tensile stress = 55 x 10⁷ Pa

The tensile stress on the wire is equal to 55 x 10⁷ Pa