Question

The value of ?G�\' for the conversion of 3-phosphoglycerate to 2-phosphoglycerate (2PG) is 4.4 kJ/mol. If the concentration of 3-phosphoglycerate at equilibrium is 2.35 mM, what is the concentration of 2-phosphoglycerate? Assume a temperature of 25.0 �C. The constant R = 8.3145 J/(mol�K)

Answer 1

0.3983 mM is the concentration of 2-phosphoglycerate.

Step-by-step explanation:

3-phosphoglycerate ⇄ 2-phosphoglycerate , ΔG° = 4.4 kJ/mol

Concentration of 3-phosphoglycerate at equilibrium = 2.35 mM

Concentration of 2-phosphoglycerate at equilibrium = x

Equilibrium constant of the reaction at 25°C =
`K_c=(x)/(2.35 mM)`

`\Delta G^o=-RT\ln K_(c)`

`4400 J/mol=-8.3145 J/mol K* 298.15 K* \ln [(x)/(2.35 mM)]`

`\ln [(x)/(2.35 mM)]=(4400 J/mol)/(-8.3145 J/mol K* 298.15 K)`

`\ln [(x)/(2.35 mM)]=-1.7750`

`(x)/(2.35 mM)=0.1695`

x = 0.3983 mM

0.3983 mM is the concentration of 2-phosphoglycerate.