Answer:
50%, 0%, 50%
Step-by-step explanation:
From the Punnet square, there are 2 heterozygous genotypes out of 4 offspring, hence, the probability that an offspring will have a heterozygous genotype is 1/2 or 50%.
There are no homozygous dominant genotype among the genotype of the offspring as seen in the Punnet square. Hence, the probability of an offspring having a homozygous dominant genotype id 0%.
There are 2 homozygous recessive genotype out of 4 genotype of the offspring, hence, the probability of an offspring having a homozygous recessive genotype is 1/2 or 50%.