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A transformer is to be designed to increase the 30 kV-rms output of a generator to the transmission-line voltage of 345 kV-rms. If the primary winding has 80 turns, how many turns must the secondary have?

1 Answer

6 votes

Answer:


n_s = 920 \turns

Step-by-step explanation:

given,

Voltage across the primary coil (V_p) = 30 kV-rms

Voltage across the secondary coils (V_s) = 345 kV-rms

number of turns primary coil have (n_p) = 80 turns

number of turns in secondary coil (n_s) = ?

the ratio of primary and secondary loop


(n_p)/(n_s) = (V_p)/(V_s)


(n_s)/(n_p) = (V_s)/(V_p)


n_s = n_p (V_s)/(V_p)


n_s = 80* (345)/(30)


n_s = 80* 11.5


n_s = 920 \turns

turns that secondary loop have is equal to
n_s = 920 \turns

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