211k views
4 votes
A volleyball is spiked so that its incoming velocity of +4.37 m/s is changed to an outgoing velocity of -10.5 m/s. The mass of the volleyball is 0.350 kg. What is the magnitude of the impulse that the player applies to the ball?

User Jsamol
by
7.8k points

1 Answer

6 votes

Answer:

-5.20 kg.m/s

Step-by-step explanation:

Impulse is another word for change in momentum. It is calculated according to the following formula

impulse = final momentum - initial momentum


impulse = mv_(f) - mv_(i) \\              = -10.5*0.350 - 0.350*4.37\\              = -5.20 kg.m/s

It is important to pay close attention to the signs to ensure that no mistakes are made. Impulse is a vector so the direction of velocity is important in the calculation because very often it determines the direction of the impulse

User Qumber Abbas
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.