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In a restaurant, the daily menu is mounted on wallboard. The printed region with today's entrees includes 216, space square inches of text. If there are two-inch margins on the sides and three-inch margins at the bottom and the top, what are the dimensions of the smallest piece of wallboard that can be used for the menu?

User Shameka
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2 Answers

4 votes

Final answer:

To find the dimensions of the smallest piece of wallboard for the menu, add the text area with the margins. The width is the width of the printed region plus 4 inches, and the height is the height of the printed region plus 6 inches.

Step-by-step explanation:

To find the dimensions of the smallest piece of wallboard that can be used for the menu, we need to consider the printed region with today's entrees and the margins.

The printed region with the entrees is given as 216 square inches of text. The margins on the sides are two inches each, and the margins at the bottom and top are three inches each. So, to find the dimensions of the smallest piece of wallboard, we need to add the text area with the margins.

The total width of the menu is the width of the printed region plus the margins on both sides. Since there are two margins on the sides, each measuring two inches, the total width is the width of the printed region plus 2 inches + 2 inches = width + 4 inches.

Similarly, the total height of the menu is the height of the printed region plus the margins at the bottom and top. Since there are two margins at the bottom and top, each measuring three inches, the total height is the height of the printed region + 3 inches + 3 inches = height + 6 inches.

Therefore, the dimensions of the smallest piece of wallboard that can be used for the menu are width + 4 inches by height + 6 inches.

User BoxerBucks
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5.1k points
1 vote

Answer:

"16 24"

Step-by-step explanation:

Because it is 2 to 3.

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User Leotsarev
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5.0k points