Question

Answer 35 and 36 fully with the way you did it not only answer!!

Answer 1

35a. We're asked to compute the ratio between the enlarged width and the original width. So we literally perform the operation:

`6.5/ 3.5 \approx 1.86`

35b. If the order is wrong the image would be shrunk instead of enlarged, with a ratio of
`3.5/ 6.5`

36. We know that

`(p)/(q)=(2)/(3)`

Observe that

`(6p)/(2q)=(6)/(2)\cdot(p)/(q)=3\cdot(p)/(q)=3\cdot(3)/(2)=(9)/(2)`