Answer:
Part 1: x = 6.2
Part 2: u = 3.46 and v = 2
Part 3: Altitude = 5.196
Explanation:
Part 1:
From the given figure, we can write
![\cos 59 = (x)/(12)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bej1ifxf640avg0yps5i89g8x2mbw5v55s.png)
⇒ x = 12 cos 59 = 6.18 ≈ 6.2 (Answer)
Part 2:
From the figure we can write
![\sin 60 = (u)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1of0t60ihu3tv5hpzjnh9cw6ha1sigrk8r.png)
⇒ u = 4 sin 60 = 3.46 (Answer)
And
![\cos 60 = (v)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/csqnvzhy8huqhjpulj8g8xnqlyxniecxxv.png)
⇒ v = 4 cos 60 = 2 (Answer)
Part 3:
Perimeter of the equilateral triangle is 18.
So, if each side is a, then 3a = 18
⇒ a = 6
Now, if we draw an altitude to the equilateral triangle then it will bisect the base perpendicularly.
If the altitude is x,
Therefore, applying Pythagoras Theorem we get
x² + 3² = 6²
⇒ x² = 27
⇒ x = 5.169 (Answer)