Answer:
6,226 tiles of 9 in are needed to cover an area of 400 square feet
Explanation:
Let
A -----> an area in square feet
t(A) ---> the total number of 9 in. tiles needed
we have
![t(A)=(144A)/(9.252)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s0iar2cnohd6wpcg2hu5pi8xet47m0631z.png)
For A=400 ft^2
substitute in the equation and solve for t
![t(400)=(144(400))/(9.252)\\\\t(400)=6,226\ tiles](https://img.qammunity.org/2020/formulas/mathematics/college/zobke11afz94vo2ga395kzeo44i0n73mq4.png)
That means -----> 6,226 tiles of 9 in are needed to cover an area of 400 square feet