Question

A 0.580-kg rock is tied to the end of a string and is swung in a circle with a radius of 0.500 meters. The

velocity of the rock is 4.50 m/s. What is the centripetal force acting on the rock?
5.22 N
23.5 N
69.8 N
15.5 N

Answer 1

23.5 Newtons

Have a nice day

Answer 2

23.5 N

Step-by-step explanation:

We are given;

• Mass of the rock, m as 0.580 kg
• Radius of the circle, r as 0.50 meters
• Velocity of the rock is 4.50 m/s

We are required to calculate the centrifugal force.

First, we need to know what is centripetal force.

• Centripetal force is the force that maintains the object in a circular motion. The force acts towards the center of a circular path.

Second we need to know how it is calculated.

• Centripetal force is calculated using the formula,

`Fc=(Mv^(2) )/(r)`

Third, we answer our question.

`Centripetal force=((0.580kg)(4.5^(2)))/(0.50m)`

`=23.49Newtons`

`=23.5Newtons`

Thus, the centripetal force acting on the rock is 23.5 Newtons