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Suppose a distant world with surface gravity of 5.20 m/s2 has an atmospheric pressure of 7.16 ✕ 104 Pa at the surface. (a) What force is exerted by the atmosphere on a disk-shaped region 2.00 m in radius at the surface of a methane ocean

1 Answer

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Answer:

899752.13598 N

Step-by-step explanation:

p = Pressure on the plate =
7.16* 10^4\ Pa

A = Area =
\pi r^2=\pi 2^2=\pi 4

F = Force on the region

When force is divided by area we get pressure


p=(F)/(A)\\\Rightarrow F=p* A\\\Rightarrow F=7.16* 10^4* \pi 4\\\Rightarrow F=899752.13598\ N

Force is exerted by the atmosphere on a disk-shaped region is 899752.13598 N

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