Question

A 75 g bullet is fired from a rifle having a barrel 0.650 m long. Assuming the origin is placed where the bullet begins to move, the force (in newtons) exerted by the expanding gas on the bullet is 14000 + 10000x - 21000x2, where x is in meters.

Answer 1

7557.875 J

Step-by-step explanation:

Assumimg we need to find work done by the bullet on the gas

The work is found by integrating force over distance

W=
`W=\int_(x_i)^(x_f)F.ds`

For the force in this problem we have

`W=\int_(0)^(0.65)14000 + 10000x - 21000x^2.ds`

=
`[14000x+10000x^2-21000x^3]_(0)^(0.65)`

=7557.875 J