Question

The ratios of the measures of the sides of a triangle is 4:10:7. Find the length of each side if the perimeter of the triangle is 252 meters.

Answer 1

First side of the triangle = 48 m

Second side = 120 m

Third side = 84 m

Explanation:

The ratios of the measures of the sides of a triangle is 4:10:7

Let us assume the common ratio of the sides of the triangle = m

So, the first side of the triangle = 4 m

Second side of the triangle = 10 m

Third side of the triangle = 7 m

Now, PERIMETER OF A TRIANGLE = SUM OF ALL SIDES

⇒ 4 m + 10 m + 7 m = 252 m

or, 21 m = 252 m

⇒ m = 252/ 21 = 12

So, the common ratio in the sides is 12.

Hence, the first side of the triangle = 4 m = 4 x 12 = 48 m

Second side of the triangle = 10 m = 10 x 12 = 120 m

Third side of the triangle = 7 m = 7 x 12 = 84 m