Question

Calcium carbonate decomposes at 1200.0°C and forms carbon dioxide and calcium oxide. If 33.0 L of carbon

dioxide is collected at 1200.0° C and is then cooled to 30 °C, what is the new volume of carbon dioxide gas?

Answer 1

`\large\boxed{\text{6.79 L}}`

Step-by-step explanation:

The pressure is constant, so, to calculate the volume, we can use Charles' Law.

`(V_(1))/(T_(1)) = (V_(2))/(T_(2))`

Data:

V₁ = 3300 L; T₁ = 1200.0 °C

V₂ = ?; T₂ = 30 °C

Calculations:

(a) Convert temperatures to kelvins

T₁ = (1200.0 + 273.15) K = 1473.15 K

T₂ = (30 + 273.15) K = 303.15 K

(b) Calculate the new volume

`(33.0)/(1473.15) = (V_(2))/(303.15)\\\\{ V_(2)} = (33.0* 303.15)/(1473.15) = \textbf{6.79 L}\\\\\text{The new volume of the gas is $\large \boxed{\textbf{6.79 L}}$}\\`