Question

Write the equation of a line perpendicular to y=0.25x-7 and passes through the point -6,8

Answer 1

18

y=14x+334 or

y=0.25x+8.25 or

4y=x+33

Step-by-step explanation:

.

y−3=−4(x+2)

Let's get this equation into the standard slope-intercept form of:

y=mx+b where m is the slope and b is the y-intercept.

y=−4(x+2)+3

y=−4x−8+3

y=−4x−5

Let's call the slope of this line m1 and the slope of the line perpendicular to it m2 .

m1=−4

In order for the other line to be perpendicular to this one we have to have:

m1m2=−1

−4m2=−1

m2=−1−4=14

Now, we cam write the equation of the perpendicular line:

y=14x+b

We can now use the coordinates of the point this line goes through to find b:

7=14(−5)+b

7=−54