234k views
5 votes
Only 40% of bowl remains how old is the bowl and use 5700 years as half life

User Klynch
by
4.9k points

2 Answers

7 votes

Final answer:

The age of the bowl is approximately 5730 years, based on it having only 40% remaining and using the half-life of 5730 years for ⁻4C.

Step-by-step explanation:

The half-life of ⁻4C is approximately 5730 years. In this case, we're given that only 40% of the bowl remains. Using the half-life formula, we can calculate the age of the bowl.



  1. Start with the original amount of the bowl, which is 100%.
  2. Since 40% remains, the amount that has decayed is 100% - 40% = 60%.
  3. Divide the amount that has decayed (60%) by the original amount (100%) to get the fraction remaining: 60% ÷ 100% = 0.6.
  4. Now, substitute the value for the half-life (5730 years) into the equation: (0.6) = (1/2)^n
  5. Solve for n by taking the logarithm of both sides: log((0.6)) = n * log((1/2))
  6. Divide both sides by log((1/2)) to isolate n: n = log((0.6)) / log((1/2))
  7. Use a logarithm calculator to find the value of n, which represents the number of half-lives: n = 0.51082
  8. Round n to the nearest whole number to get the number of half-lives: n ≈ 1.
  9. Multiply the number of half-lives by the half-life (5730 years) to get the age of the bowl: 1 * 5730 years = 5730 years.

User Thomas John
by
4.4k points
3 votes

Answer:

Step-by-step explanation:

40/50=0.8

0.8*100=80%

Taking 80% of half life

=80/100 *5700

40% of bowl is = 4560 years

User Mrz
by
5.5k points