Question

A traveler pulls on a suitcase strap at an angle 36° above the horizontal. If of work are done by the strap while moving the suitcase a horizontal distance of what is the tension in the strap?

Answer 1

74.79N

Step-by-step explanation:

The question is incomplete. Here is the complete question.

" A traveler pulls on a suitcase straps at an angle 36° above the horizontal. If 908J of work are done by the strap while moving the suitcase a a horizontal distance of 15m, what is the tension in the strap?"

Work is said to be done if an applied force cause an object to move through a distance.

Work done = Force F × perpendicular distance d

Since the strap is pulled at ana angle above the horizontal,

Work done = F ×d cos(theta)

Given workdone = 908Joules

d = 15m

theta = 36°

908 = F × 15cos36°

F = 908/15cos36°

F = 908/12.14

F = 74.79N

The tension in the strap = 74.79N

Answer 2

Tension, T = 74.82 N

Step-by-step explanation:

It is given that,

Angle between the suitcase and horizontal,
`\theta=36^(\circ)`

Work done, W = 908 J (let)

Distance covered, d = 15 m (let)

We know that the work done by an object is given by the formula as :

`W=Fd\ cos\theta`

here, F = T

`W=Td\ cos\theta`

`T=(W)/(d\ cos\theta)`

`T=(908)/(15* cos(36))`

T = 74.82 N

So, the tension in the strap is 74.82 N. Hence, this is the required solution.