Answer : The volume of gas at STP produced are 45.0 L
Explanation :
First we have to calculate the moles of ammonium perchlorate.
![\text{Moles of }NH_4ClO_4=\frac{\text{Mass of }NH_4ClO_4}{\text{Molar mass of }NH_4ClO_4}](https://img.qammunity.org/2020/formulas/chemistry/high-school/hz1wnw57qmzotep65mvmeps57kskkpte1g.png)
Molar mass of
= 117 g/mole
![\text{Moles of }NH_4ClO_4=(235g)/(117g/mole)=2.01mole](https://img.qammunity.org/2020/formulas/chemistry/high-school/8vy6obdln4ccz40edhya30ja4rz42j13x2.png)
Now we have to calculate the moles of
gas produced during the reaction.
The balanced chemical reaction is,
![3Al(s)+3NH_4ClO_4(s)\rightarrow Al_2O_3(s)+AlCl_3(s)+3NO(g)+6H_2O(g)](https://img.qammunity.org/2020/formulas/chemistry/high-school/hm2vvoyqh8vqts752az4i4v9p0sqsf0us1.png)
From the reaction we conclude that,
As, 3 moles of
produces 3 moles of NO gas
So, 2.01 moles of
produces 2.01 moles of NO gas
Now we have to calculate the volume of gas at STP.
At STP, 1 mole of substance occupy 22.4 L volume of gas.
As, 1 mole of NO gas occupy 22.4 L volume of gas.
So, 2.01 mole of NO gas occupy 2.01 × 22.4 L = 45.0 L volume of gas.
Therefore, the volume of gas at STP produced are 45.0 L