Question

How many grams are in 7.8 mol of ZnS04?
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Answer 1

To find the mass in grams of 7.8 moles of ZnS, multiply the number of moles by the molar mass of ZnS, which is 97.44 g/mol, resulting in 759.832 grams.

Step-by-step explanation:

The question asks for the conversion of moles of a substance, specifically ZnSO4 (which seems to have a typo and should be ZnS, zinc sulfide), into grams. First, we must identify the correct molar mass of zinc sulfide. According to the provided information, the molar mass of zinc sulfide is 97.44 g/mol. To convert moles to grams, we multiply the number of moles by the molar mass of the compound:

7.8 mol × 97.44 g/mol = 759.832 g

Thus, there are 759.832 grams in 7.8 moles of ZnS.

Answer 2

The answer is 0.0061941519772353.

We assume you are converting between moles ZnSO4 and gram.

You can view more details on each measurement unit:

molecular weight of ZnSO4 or grams

This compound is also known as Zinc Sulfate.

The SI base unit for amount of substance is the mole.

1 mole is equal to 1 moles ZnSO4, or 161.4426 grams.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between moles ZnSO4 and gram.

Type in your own numbers in the form to convert the units!

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