Question

In an experiment, 100 mL of acetone is dissolved in 1.5 L of water to make a solution. Which of the following calculations would be best to describe the concentration of acetone in the solution?

A. volume/volume percent
B. equalities
C. g/L
D. 22.4 L/g

Answer 1

volume/volume percent

Step-by-step explanation:

You have a liquid solute and a liquid solvent. Therefore, it is appropriate to use volume/volume percent.

I just wanted to say that this is the correct answer! The other answer on here has a much better explanation, and even helps you with the actually problem/math. Go check it out! :)

Good Luck! <3

Answer 2

Option A %V/V

Step-by-step explanation:

First, let's remember the basis. A solution is made with two components. A solute, which is the component that it's usually at lower proportions, and it will be dissolved into another component. The solvent which is the medium that will dissolve the solute. This component is usually water and it's on higher proportions.

In this case, we know that the components are acetone and water. According to this, we have only 100 mL of acetone, and 1.5 L of water, therefore, the acetone is the solute, and the water is solvent.

The solution is as following:

Solution = 100 + 1500 = 1600 mL of solution

Both components are in volume units, therefore, option C and D, cannot be correct answers. Now, if the exercise gives us some data of density or any data to convert the volume to mass in grams, we cannot express the concentration of this solution in grams, because all of the data is in volume units.

The %V/V is:

%V/V = Vsolute/Vsolution * 100

And replacing data we have:

%V/V = 100/1600 * 100 = 6.25 %V/V

And this would be the correct way to describe the concentration of acetone.