Question

An unknown diatomic gas has a density of 3.164g/L at standard temperature (273K) and standard pressure (1.00 atm). At standard temperature and pressure, one mole of any gas occupies 22.4L of volume. What is the identity of this gas? Show your work to explain why.

Answer 1

Answer : The unknown diatomic gas is chlorine
`Cl_2`

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

`Density=(Mass)/(Volume)`

Given :

Density of unknown diatomic gas = 3.164 g/L

Volume of gas at STP = 22.4 L

Now put all the given values in the above formula, we get the mass of the unknown diatomic gas.

`3.164g/L=(Mass)/(22.4L)`

`Mass=3.164g/L* 22.4L=70.9g`

Thus, the mass of unknown diatomic gas is 70.9 grams that means the unknown diatomic gas will be, chlorine
`Cl_2`

Hence, the unknown diatomic gas is chlorine
`Cl_2`