Question

Pls helpp 13 points !!!

Answer 1

The angles are : 85°,85°,70° and 70°

Explanation:

to find the measure of each labeled angle.

For the given parallel lines:

`5x\° =(3x+34)\°` [ exterior alternate angles of a traversal between parallel lines have same measure.]

Solving for
`x`

Subtracting both sides by
`3x`

`5x-3x=3x-3x+34`

`2x=34`

Dividing both sides by 2.

`(2x)/(2)=(34)/(2)`

∴
`x=17\°`

Measure of angle =
`5* 17\°=85\°`

`2y\° =(3y-35)\°` [corresponding angles of traversal between parallel lines have same measure.]

Solving for
`y`

Subtracting both sides by
`3y`

`2y-3y=3y-3y-35`

`-y=-35`

Dividing both sides by -1.

`(-y)/(-1)=(-35)/(-1)`

∴
`y=35\°`

Measure of angle =
`2* 35\°=70\°`